4(-x^2+1)/(x^2+1)^2=0

Solution for 4(-x^2+1)/(x^2+1)^2=0 equation:

4(-x^2+1)/(x^2+1)^2=0


Domain of the equation: (x^2+1)^2!=0

x∈R


We multiply all the terms by the denominator


4(-x^2+1)=0

We multiply parentheses

-4x^2+4=0

a = -4; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-4)·4
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*-4}=\frac{-8}{-8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*-4}=\frac{8}{-8}
=-1
$